5x^2=10x-4=0

Solution for 5x^2=10x-4=0 equation:

5x^2=10x-4=0

We move all terms to the left:

5x^2-(10x-4)=0

We get rid of parentheses

5x^2-10x+4=0

a = 5; b = -10; c = +4;
Δ = b2-4ac
Δ = -102-4·5·4
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{5}}{2*5}=\frac{10-2\sqrt{5}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{5}}{2*5}=\frac{10+2\sqrt{5}}{10}
$